divide 12 into 6 one side n balance it..5.39.217.76; F3 @% R6 s& T8 }5 n; t+ i8 u
den take da heavier side which is 6 n divide into 2 parts again..
; s! R s& \7 e/ D3 one side n another 3 another side..! T8 [# ]1 k/ V' R a; O
den u take da heavier part again..
+ m; b$ _6 D; C, b0 W. E+ R公仔箱論壇now u left 3 pingpong.. u can simply choose 2 of it n balance again..5.39.217.76( }* u, w9 ^, J" D0 j
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |