take out 10 balls and 5 in each side2 V5 B( P8 S$ A, \! C
if both side balance mean the other 2 balls one of them must be the heavy one then just take them to weight will find out which one is heavier.( X. g1 {- [& {! F! y
+ r$ h6 g. d/ v; w) u3 y
if the heavy ball is inside the 10 balls, take out 4 balls from the heavier side which had 5 balls to weight 2 balls in each side.
- w, p( k3 j9 }4 v8 H( n/ `7 ^tvb now,tvbnow,bttvbif both side balance, which mean the one left is heavy one if not, just take the heavier side to weight will find out which one is the heaviest one.
# g- q# P+ J% q: r/ etvb now,tvbnow,bttvb
/ a: b6 S5 a6 Q1 o. ?! K! n& Cused less then 1 min to find out the answer.... |
發表於 2007-12-31 05:47 AM
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發表於 2008-1-1 08:48 AM
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