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let me see
以前聽過, 覆查答案..
識做啦..都唔使30分鐘咁耐..
1. test 3 by 3 as the first test
- C! [& G- z+ u8 u2. if the first test balls are not the same, take 2 from the heavier side and one from the lighter side on the balance, put the normal 3 at the other side of the balance.
0 ?- \* J( U$ \6 Z& Dtvb now,tvbnow,bttvb3. if the normal one is heavier, 2 steps is enough as the lighter one what we look for.
" W( v3 h' S" G* z5 |1 A; itvb now,tvbnow,bttvb4. if the normal one is ligher, check the 2 heavier one and look for heavier one.
7 Q3 G, ?# Z3 f2 q) Y( L% @5. if the balls are the same at the first test, take 2 balls from the reminding and see if they are the same. If yes, the reminding one is the answer. If they are not the same test it with the reminding ball...
好難.. :$
咁都叫IQ題......簡單都唔信......唔駛三十秒都諗到啦
相当难的题目。。看看吧
等我试下先!~~
看答案
what is it?
GOOD GOOD ... HEHE !!!!
thanks
seeeee
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