ericchan1

好難呀．．．

eleven20

難...

jeffreyhohoyuan

好難呀．．．．

百事可乐

ddd

dimsum199

好難喎

PokChop

There is 12 balls.. divide them into piles of 42 j, F) n9 ~* ^, B$ J
so 3 groups for 4..name is A,B,C
9 T3 e/ Q, E9 s  S8 E公仔箱論壇case 1:
& `  Z) n* M% c# R5.39.217.76measure A -- B tvb now,tvbnow,bttvb$ R1 J1 N! O' ?1 J3 o, X
A or B is heavier TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。: w8 ?0 r8 B+ x6 c6 D, q
divide that group into 2 by 2! n' H- g9 q5 I! e
then divide heavier group into 1 by 1
7 t' W. H* P- f6 ?! J4 {0 U公仔箱論壇5 ~# \. U" Y1 [) Z% W" ?6 y
case 2:tvb now,tvbnow,bttvb) @, p4 V/ e& X& @
A and B is the same.. therefore C has the heavier ball
" Z4 v  n4 ~# [8 q. Vdivide C into 2 by 2
$ ?2 |9 b' u# h: }$ z2 _0 ZTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。then divide heavier group into 1 by 1..
! B8 R) t1 p( T% w( {
$ ~% v/ `5 A' p! O$ a) u( Ugot it in 30 seconds.. not so hard -.-'

curlihead

thx

curlihead

i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。- j& c; k* i/ x0 x
5.39.217.76- G' i( t+ a5 r$ s0 F& W
they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.

boringaya

睇下先

mm_penguin

do this is so boring...8 ]7 f+ V' I4 S& U
play game la~~~

306247000

[-X OK la^:)^ ^:)^

diy123

一知道有答案睇就唔想谂咁耐了

hey8hey8

?

magcsm

why?

jackytan3344

多謝大大的分享