lux1261

答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1

lesley

^:)^ >:D<

leekh

thx

jc49

let cc

Special_Forces

not possible

sm911118

不知道要怎麼做阿??

laou

hao

jen198053

there got more simple way to do it, just read my way, the one i answered before

samkk123

the

hakis

see 了

jenfien

第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了

fxenon

how?

nyb

先分3个一堆" U6 E1 n: o3 J! T/ r1 w0 O
共四堆公仔箱論壇+ z9 X, d! C+ w) r0 \1 g
称两次得出异常的在那一堆，其轻重
7 L, {  c' D: w( W% y+ |0 K2 S3 |5.39.217.76在异常的那一堆中在称一次2 `- p: E7 K  D) E/ o: }
就可以找到了

ceteriz

divde the 12 balls into 3 sets of 4. 3 Y2 E8 k- z' w( ^  v/ v. E( C* U
weight any 2 sets.
+ o7 W5 C* g/ C$ L! h3 k; }1 Ntvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
* [: T- M1 `& ]/ Q& j2 e公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set3 s# K7 Y2 ], ^" ?( ]% t+ J. q6 W
then divide the 4 balls into 2.5.39.217.76- g  g4 s/ P* W8 C3 V
weigh them
) `* ~7 I' e% g& l  @公仔箱論壇and divide the heavier into 1
+ p+ f  z4 G' v9 @" L1 dand weight them.5.39.217.761 P' C' [; B% ^2 J
3 x weighing and get the ans.  
( Z' s6 |5 Y2 V, e( Lin less than 15 secs.

kino_kino

1. 6 aside and weight.0 z6 c0 t: ]- I; L3 G
2. heavier side from (1), 3 aside weight again.
: k; i9 |' E' X' n5 y$ a0 d公仔箱論壇3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
7 v, r2 ?& M1 G5 F" V7 jtvb now,tvbnow,bttvbTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。8 Q( O. O0 }8 o/ _* K5 p$ ?
but i have a question. 重量異常 can be heavier or lighter.... so......