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easy, one minutes i solve the problem" Z  {5 H2 K: c, v
divide into half, mean 6/ 6
. S; o4 H/ C- W5 ztake the heavier 6 ping pongtvb now,tvbnow,bttvb/ K3 I2 h/ L* }- o$ G0 |9 z5 f; h
divide into 3/3, take the heavier 3
' h% J* t7 x4 H/ ^5 d( Mtake the the other 3 that have the equal weight, switch each to measure, the most important things is labeling the ping pong so that we can recognize
量3 次, 一次 6比6, 一次3比3, 一次1比1, 就可以找出来了
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