Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group.tvb now,tvbnow,bttvb+ Z& b k3 s5 ?
The problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once.2 {; [( g( G( [0 J! @ v0 ?
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發表於 2008-10-15 03:38 PM
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