tcmhw

divide 12 into 6 one side n balance it..5.39.217.765 T% I! f5 M( |4 q9 |& b5 H
den take da heavier side which is 6 n divide into 2 parts again..
! \( b3 \& z* c, d$ U3 one side n another 3 another side... A; y& \! X- S( x. p
den u take da heavier part again..
9 N( n! p* {6 o6 C  x) Anow u left 3 pingpong.. u can simply choose 2 of it n balance again..
9 K# Q4 {! W& ^* K3 u* A公仔箱論壇if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan