anakmalas

this is too easy!!. Z$ x* d, S; t1 f
5.39.217.766 F; B; X7 N: H" }5 y! ?
1. put 6 at each side.. take the one side which is heaviertvb now,tvbnow,bttvb9 i$ T. }: s5 r. o4 G
2. put 3 at each side.. also take the heavier side
5 }. W' }/ J3 x2 j+ _* |2 K$ H5.39.217.763. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball..