number 4 has the best chance to live
% d, {& f* u1 \: nTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。assume number 1, 2, 3 and 4, pick number a, b, c and d.5.39.217.76* U. x+ Q* F9 Y- L% s; x
number 4 knows how many left in the bag which is 100-a-b-c
5 n* P! Y. ^. d# a C1 \公仔箱論壇take the average of (100-a-b-c)tvb now,tvbnow,bttvb8 J; Z, b8 Z) y5 D% D1 S# I
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 J7 E0 x4 n: ^4 \* T" H C& _( S$ [
and number 4 can squeeze himself into the average and what number 5 picks.% ^6 x i* u$ H m; `" B% {2 {4 K
so number 4 will have the best chance.5.39.217.76, y( ~% P4 K* `# m0 q; D- ]
9 c' w. h( h) j- s. q K7 q) q" @5.39.217.76i hope this is a good logic hehe |