number 4 has the best chance to live
: z/ W$ r T: W# w* \5.39.217.76assume number 1, 2, 3 and 4, pick number a, b, c and d.
0 h3 L w& u, S. q5.39.217.76number 4 knows how many left in the bag which is 100-a-b-c
8 E" h0 I3 |# O& o/ P* Mtake the average of (100-a-b-c)
' F8 _' @* t9 T O7 e7 h5 e' | ~公仔箱論壇then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)8 Y# f: S0 N5 m% b+ ?
and number 4 can squeeze himself into the average and what number 5 picks.5.39.217.76 m2 o6 O w4 v# E
so number 4 will have the best chance.
m7 \. j" o5 {6 U* t5.39.217.76
" c' |. B& X$ S, ci hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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