loveallcar

number 4 has the best chance to live' p# u( s3 p* Z0 L. O
assume number 1, 2, 3 and 4, pick number a, b, c and d.
, S- y% x, ]( e( |4 itvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-c
5 ]8 V. a0 [' F$ {5.39.217.76take the average of (100-a-b-c)
4 T& A7 R+ Z) I5 I- Lthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
3 v7 E! P6 ~  _# @公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
" b. Q$ p3 G7 ]% `- G* utvb now,tvbnow,bttvbso number 4 will have the best chance.
) k$ l4 ?  ?* J6 T( I& @  f5.39.217.769 E2 S+ l7 \8 @) p! n
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
' c) \9 L+ e0 yplease post answer la5.39.217.76* Q5 b' d2 E+ m
can't wait la