loveallcar

number 4 has the best chance to live5.39.217.76; e  m& J- H! E' N4 K
assume number 1, 2, 3 and 4, pick number a, b, c and d.
; ?  k  b( f; e! B) I' I/ [1 m5.39.217.76number 4 knows how many left in the bag which is 100-a-b-c8 @3 H5 _. G$ _9 a2 P
take the average of (100-a-b-c)
4 G; c/ w/ h  P! F5 Z4 f2 }公仔箱論壇then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)6 W0 d3 X2 {- Y! s% }2 C
and number 4 can squeeze himself into the average and what number 5 picks.tvb now,tvbnow,bttvb5 B5 U4 j; d4 W- f, e$ E
so number 4 will have the best chance.
. F7 ^& q9 o: P$ e4 P  _  V* h) y- L5.39.217.76  |5 {- n2 _) Y) p7 C1 ]
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.tvb now,tvbnow,bttvb6 H7 R) @* V/ M) ]
please post answer la
3 s) D- h2 O) V4 ~# W) s9 {tvb now,tvbnow,bttvbcan't wait la