loveallcar

number 4 has the best chance to live
, t0 h' a% |  o5 w0 fassume number 1, 2, 3 and 4, pick number a, b, c and d.
* x! v2 k7 }6 V% X1 I, ftvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-ctvb now,tvbnow,bttvb- w. {4 y  _1 [& W- ^' Q
take the average of (100-a-b-c)
4 d8 P0 B' X; k& }( M5 p  o3 o5.39.217.76then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
5 Y/ T! X& \/ M  A" U1 i2 N: TTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。and number 4 can squeeze himself into the average and what number 5 picks.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' _$ G" A7 ^7 r3 U3 D/ p! O) @
so number 4 will have the best chance.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ s& n3 E! t4 x3 Y
; e. p0 i5 y6 g
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.6 y. g) r2 }5 O% \+ H( s+ o
please post answer latvb now,tvbnow,bttvb: j% i: c. `& v/ o$ T% d( D' \
can't wait la