number 4 has the best chance to live
$ V/ A0 V4 \: F1 ?tvb now,tvbnow,bttvbassume number 1, 2, 3 and 4, pick number a, b, c and d.
; R" W P) G# d8 e9 [7 u公仔箱論壇number 4 knows how many left in the bag which is 100-a-b-c3 D6 z6 K1 B5 \
take the average of (100-a-b-c)
2 P' V5 ?: H0 [1 ?+ J9 W% |then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)公仔箱論壇" S; N- L% K! q5 }: S' S
and number 4 can squeeze himself into the average and what number 5 picks.* d" q2 W, A X4 G5 B- J7 u
so number 4 will have the best chance.
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: r) Z( S2 y- I2 Q. n5.39.217.76i hope this is a good logic hehe |