That is a very simple mathematics question.# l. K& a7 @$ q
Let x = Male, y = Female, z = Child 5 Q- `, g/ W" C8 _% t. C% d6 P" ?" z( Otvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb% q: r+ v5 H( d& F, I6 `3 `1 q5 J
x + y + z = 100 Formula 2- H& G7 y5 @2 }% a1 R
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb7 G$ F6 T( z& V: J y w& Y
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb3 t; h% D- Y+ v8 G/ v( J
Formula 4 can change into 11x + 5y = 100 Formula 5+ W# j/ Y9 L8 u% d- f# @0 W
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb3 M4 Z6 f7 J4 b
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 7 Y/ R* L8 H: z! m+ Y公仔箱論壇Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,childrentvb now,tvbnow,bttvb5 L; Z, S) I3 K$ {8 L9 p+ S
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM