That is a very simple mathematics question.( j& M2 q' R1 v' E) ]! E( P, i
Let x = Male, y = Female, z = Child$ R9 [# W' B- s& W8 g
6x + 3y + z/2 = 100 Formula 10 ^. J3 L7 u% |5 G
x + y + z = 100 Formula 2 5 b6 G! M4 o0 ^, l ^# u5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 : N4 i% ?# y$ Q' {5 utvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% {3 U7 e6 S5 @8 V" k" G; I
Formula 4 can change into 11x + 5y = 100 Formula 5 6 Y9 u+ h8 ?& W& x5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.9 p6 D: i- w- \6 e" y9 `1 g
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. ! x" F" P3 m. B; x& [& Itvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
5.39.217.76/ e. b, d n. o0 e$ x. ?
11X must be 0 or multiple of 5 3 z+ d2 L' c/ Q" L: L; v5.39.217.76that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM