That is a very simple mathematics question. H2 |- y% @: q8 B0 ^: ULet x = Male, y = Female, z = Child% e; d( ^: B7 c8 a( L
6x + 3y + z/2 = 100 Formula 1 / m2 T+ z0 W$ d2 X: y, Mx + y + z = 100 Formula 2 q2 M6 L5 l: u! M7 k
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb# z* G' a" `4 ^7 e4 e
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇% @9 {7 ~# v' N
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇+ d8 N( t; A& Y1 O1 u6 J$ s
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. - l0 Z: ~$ z ~5 K9 G" h7 _, B% iTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇6 c% Q, `2 \( t5 v3 i
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers