That is a very simple mathematics question.5.39.217.76& y, f8 R3 s. h; X+ j
Let x = Male, y = Female, z = Child % }7 O* j. y, D* A+ I& H* C2 c) ctvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1公仔箱論壇- Y7 s( S( u% n1 y) O/ ]( E
x + y + z = 100 Formula 2 1 p( j: H2 A6 K3 R& `% x- ^ Mtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3% Z h( n# g7 I6 F
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4, k$ l7 q; F8 G+ `- N* [) @8 [
Formula 4 can change into 11x + 5y = 100 Formula 5' [) I/ t( S; {/ B U
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. # m- q5 {3 o) c$ |TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb) c/ n; D {, e
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers