That is a very simple mathematics question.tvb now,tvbnow,bttvb# q1 H! {* }( X. v
Let x = Male, y = Female, z = Child5.39.217.76$ Y7 ^' d) w: P8 |
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb! t8 i. K0 h$ n. ?8 F
x + y + z = 100 Formula 2 G! S8 M0 Z' w) y5 B! j9 H- X公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb9 z. v; Q2 A7 h9 D; k0 S4 m
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb N6 P }* b" h c& f
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇 S" B/ e- d1 H9 w6 @
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. # S: x u8 X. s1 E# Z2 _And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 1 @9 u8 i$ G. {: `' A+ C, KEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children . W b; X2 {' \1 t- Ttvb now,tvbnow,bttvb0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
