That is a very simple mathematics question. * ~7 ?% e- p+ _7 D1 f) B$ btvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child- ]/ m) h; M2 w2 V' Z3 c
6x + 3y + z/2 = 100 Formula 1 1 n- X: h' d) \- h+ g公仔箱論壇x + y + z = 100 Formula 2; O/ o# f: i0 Q" [5 T
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.765 |9 t# Y( N# I) c4 y5 I1 @1 n
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 . l2 _! ~/ A6 g5 ?4 |公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76' j0 I* \) k9 s' ~, O" q/ j
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. n, }6 X0 Q/ K' w% Y) }
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb$ v( F% P! r2 x8 _: y& i
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
! }+ r$ s/ u8 F& _- w, }5.39.217.7611X must be 0 or multiple of 5 2 @/ V! a a( D0 U- Q `; hTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
