That is a very simple mathematics question. 1 E" H) ~1 M5 q/ s5.39.217.76Let x = Male, y = Female, z = Child$ `8 m' F! u6 h- S6 Z" d6 W1 U
6x + 3y + z/2 = 100 Formula 1 2 ]' U4 z; s1 ] }9 e% u5.39.217.76x + y + z = 100 Formula 24 y, P9 e- Z$ _% ~
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35 o! }( f4 Q; O( j/ v
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 + j8 `( B5 s( {0 G0 C5 ?公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5# T; T" E% V) h
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 6 r; c* B! T# p9 e* uTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.3 |9 X* I) j9 G1 D L
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
; q9 K6 P) q c* c; l. e7 R/ k5.39.217.7611X must be 0 or multiple of 5tvb now,tvbnow,bttvb/ v6 p6 j8 T+ |: `( y
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM