That is a very simple mathematics question. K4 x! c! A d( ^ w+ GTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child: H8 Z, Y# y- b# l
6x + 3y + z/2 = 100 Formula 1 2 B- U8 H; F4 |$ r* gtvb now,tvbnow,bttvbx + y + z = 100 Formula 2 8 p) K9 o* E# {6 cSimplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇3 M. i& M$ H5 E
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 c! |% H' \, K8 `9 ]8 c5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb! Q8 P1 S3 E1 g0 y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76. E0 }$ `5 R8 F
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. : S* @, H( i0 i6 F公仔箱論壇Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children5 _* g2 ~$ l" {0 w
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM