That is a very simple mathematics question.tvb now,tvbnow,bttvb" z, b; J6 O$ c+ W" L* s( w9 P# n
Let x = Male, y = Female, z = Child* ]! ]( h% t1 A
6x + 3y + z/2 = 100 Formula 1 + b' @- W; b. H% @/ x5 D. px + y + z = 100 Formula 2 , J, S3 K2 u7 d( q1 SSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb" {9 r: ^$ B/ S2 x% D( H5 H" @
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4$ c& H, I, b8 U$ I3 r$ F9 p
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb& f4 {+ a& \5 w2 U; e
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb9 e( {# e) r7 U0 s0 V3 C# O% b
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb7 _6 J/ c& r ~$ W
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children 2 D5 ?9 i& } E' i& ~0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
公仔箱論壇; |+ V' g0 m) ?/ [
11X must be 0 or multiple of 5tvb now,tvbnow,bttvb, S8 l$ B) B0 a+ Z6 T, [2 }, k5 N$ D" Y
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
