That is a very simple mathematics question. 1 J( k6 D, X( r- F# C i( N. qLet x = Male, y = Female, z = Child 8 W2 J$ d4 x. w( a1 Y2 @6x + 3y + z/2 = 100 Formula 1 ) x: a* `# o$ ] J3 C! h$ k公仔箱論壇x + y + z = 100 Formula 2 _2 o# k3 c# T( P' Y V tSimplify Formula 2 into z, we get z = 100 - x - y Formula 3 ( d+ l3 E# {$ ~5.39.217.76Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 # T! q# l8 b( B3 h$ }( KTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 55 q% H' x# X' s+ I" l U' v% w/ x
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.. e" ] I0 a$ z6 p
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 7 c" F6 I( k5 F! h$ mEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children" Z1 _, U. K6 I% R+ H: V/ o
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
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11X must be 0 or multiple of 5/ e# ?$ P7 T5 P) ^) T# \$ o
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
86 children " I, y0 p( h% F5 male 5 O7 f( V3 N8 v. _. y# @! U( n
9 female作者: dafunhei123 時間: 2007-10-15 10:39 PM
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