That is a very simple mathematics question. 0 e! w" h& J* kTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child/ H" J7 Q* U. L) c6 z
6x + 3y + z/2 = 100 Formula 1, R* U5 [, P7 l% {5 I1 v
x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) j5 W: ]# L) _, R
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 4 Y+ s4 k9 y( W8 H( G- pTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇4 M$ i( G* F. A
Formula 4 can change into 11x + 5y = 100 Formula 5 & V6 H& J4 \2 o7 [* o8 Q d. [1 [5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. ) E1 J# v; U* A8 l7 p4 Q Q+ ntvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.* Q% i( J# S0 q, T6 A8 S
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers