That is a very simple mathematics question. {4 V7 o" W: k+ a
Let x = Male, y = Female, z = Child5.39.217.762 ? C* C; {) e' C; j5 ~6 b: M
6x + 3y + z/2 = 100 Formula 1 * y. n4 x' Q6 w$ o, D) p4 \x + y + z = 100 Formula 2 ! B) v. G( D" [* q5 uSimplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。; e7 c2 d" I0 t) W, k L+ ~( V
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 8 A. L9 ^4 H) N! \/ h5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5; t, L+ n2 a) [
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 1 n0 x/ \6 ]/ ], Y5.39.217.76And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 0 A0 q6 I$ R) `9 l1 kEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
+ e, n4 z% l$ D0 ^9 W5.39.217.7611X must be 0 or multiple of 5tvb now,tvbnow,bttvb* M; {8 o0 {# q# x' @
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
86 children' T9 ~$ f H, r: n
5 male 5.39.217.76) A* t9 s! m# \2 F4 Y7 V+ ]
9 female作者: dafunhei123 時間: 2007-10-15 10:39 PM
