That is a very simple mathematics question., a. a) P" W! {+ s
Let x = Male, y = Female, z = Child: l/ `! n1 a! H1 e7 B3 D" Q* z3 m
6x + 3y + z/2 = 100 Formula 15.39.217.763 |6 D( a7 {8 Q. w3 A u
x + y + z = 100 Formula 2 : P6 z( G, T, [8 _. f3 ESimplify Formula 2 into z, we get z = 100 - x - y Formula 3+ g) T$ u1 ^0 A8 F& m0 y
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 45.39.217.76( Q' P* T% o- }
Formula 4 can change into 11x + 5y = 100 Formula 50 k7 r" Y- r! \5 k/ c
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.3 L' J2 M& v1 N+ t5 g
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. ! j7 K6 |* h' F) o/ I& O9 bEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
