That is a very simple mathematics question. 8 z: ]+ d9 A6 C& v7 M! \tvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child ' i* j8 B/ L* ^9 j8 H. m6x + 3y + z/2 = 100 Formula 15.39.217.76/ g; t" N5 `1 w: X" X+ }2 J. X( \! k' C2 g
x + y + z = 100 Formula 2 . b$ n4 [# i4 A* FSimplify Formula 2 into z, we get z = 100 - x - y Formula 3& H' C* b6 W6 v
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 ( ]1 t, o$ p9 @, X' g# k公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.760 `) T( O* g- l8 ^0 f
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 1 }( L3 M$ k, |# ^6 c. o' }: U公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 5 w/ \2 @% p1 bEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
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11X must be 0 or multiple of 5TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。5 Q4 Q6 M9 F$ c5 _
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
