That is a very simple mathematics question.4 `# c- i4 p0 O% ]1 a7 ^ \8 G
Let x = Male, y = Female, z = Child5.39.217.766 C7 F+ H r* G1 V8 Z' g
6x + 3y + z/2 = 100 Formula 13 c) s6 f5 S& ?# I
x + y + z = 100 Formula 2 0 i# Z* C+ w/ P8 [9 z8 j1 }0 Ftvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3 ( \ q2 d4 ^0 A, o. Y5 Mtvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 $ D2 l! y8 Z& N' u1 k) U) qtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5 8 d0 o) B' V0 r- J6 B3 v. i9 s5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. $ g0 w9 f2 P& |, L5.39.217.76And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. ) H* `) M" o6 }% Q6 ]+ j) v0 bEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children" Q# _9 j: A- y6 A# e8 Q/ f
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM