That is a very simple mathematics question.tvb now,tvbnow,bttvb8 z( ~ L' @! W$ ~) I2 Z
Let x = Male, y = Female, z = Child 8 q% j; `) e+ p0 S) W0 u, d- v* |: X" F' k) tTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1 ( z8 n. B* k( D( {" c9 _! Jx + y + z = 100 Formula 2tvb now,tvbnow,bttvb9 t! A/ j; X9 u& l7 a2 y' H
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3. k4 E1 J6 ^! ?2 @$ Y9 L
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 7 B2 V6 Z1 ^# utvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5; [9 n/ _- L. q; v3 _" q% F( r
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.) F' j! R4 X4 o) q8 Z- L2 T
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: Q+ _6 A9 i! `& C" d9 Z
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers