That is a very simple mathematics question. 1 G) L. r/ P, s5 Y4 e/ xLet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb1 H9 {0 ]$ g% k+ q# f$ ~ N
6x + 3y + z/2 = 100 Formula 1 . _. u g. |4 c* M3 B/ s2 k9 n5.39.217.76x + y + z = 100 Formula 2 * r8 d% r2 c- g) B' |9 ~/ GSimplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。( w9 d7 S8 g+ Q; d/ @! E7 Y
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 8 W& A" }5 J/ @7 c4 e1 H/ J公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5, j9 Q% C) e& e7 g7 j
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 0 U7 ]: b; C; @* t公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. : N" I9 c3 S* Y8 Q( I BEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
6 E6 P. @# o2 m: S* H# o5.39.217.7611X must be 0 or multiple of 5tvb now,tvbnow,bttvb; w8 i5 I7 W. M7 G1 Z
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
公仔箱論壇; A; v/ R; D+ W, M( R# G
