That is a very simple mathematics question.5.39.217.76' A9 C% h! {* U* [+ T9 \2 b
Let x = Male, y = Female, z = Child , }- P- ^3 s" Q% I4 p1 x Stvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 15.39.217.76. A8 U# Q, [- ^' V1 x; L U
x + y + z = 100 Formula 25.39.217.76% U+ o" b% }6 M* q) M2 D( Z
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.76, d" T0 ] f" Y, |
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 6 g+ p/ V/ H( e, U5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5 $ }8 b+ h" Z+ B1 D ]/ o5 O; C5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.) q/ [2 R. p1 u+ a7 q
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb, x6 P2 o8 M) s( n1 a$ z
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。9 u* o4 v9 D; f2 h
11X must be 0 or multiple of 5 . M! J1 ^: B& s% `that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
