That is a very simple mathematics question. , R4 }+ A" u+ h) p- |0 h. @Let x = Male, y = Female, z = Child - K) S3 M" P' T- O( j8 x6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 {- }; j) D9 ~% Q5 j
x + y + z = 100 Formula 25.39.217.768 m* d3 d' P1 o3 D2 W6 e7 X
Simplify Formula 2 into z, we get z = 100 - x - y Formula 33 h6 ^9 k2 P: Y
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 45.39.217.767 P$ r! V- R3 q! f5 x4 B
Formula 4 can change into 11x + 5y = 100 Formula 5 1 _' c* i- m" m- f) i& ^4 M. rIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want./ f- P* [; C3 _1 n/ ]
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇- m _- q* z& o* a; c
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
公仔箱論壇+ |2 R j4 \6 M+ _$ C' x9 B1 a" r, m
11X must be 0 or multiple of 5 * s+ K( B0 z( c* D. `tvb now,tvbnow,bttvbthat meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM