That is a very simple mathematics question.5.39.217.76# q$ m" M5 y. s
Let x = Male, y = Female, z = Child. M0 C. O5 A& ?! w5 C
6x + 3y + z/2 = 100 Formula 1 $ ?6 D5 E: D. ztvb now,tvbnow,bttvbx + y + z = 100 Formula 2tvb now,tvbnow,bttvb) R/ Q. v0 s* V d0 W
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 9 P6 ]0 [( N( B- G' X; w/ |tvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 ' r$ x9 y2 N2 B3 nFormula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇8 c) F' I i2 a2 i h X
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. ; `% N& V3 M8 Z& X- a! h6 E公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. ' D# p# c. N0 a9 t公仔箱論壇Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
原帖由 twinsdragon 於 2007-10-13 05:40 PM 發表 tvb now,tvbnow,bttvb" Y2 A/ f4 N, `* R
11x + 5y = 100 Formula 5
& ?7 ?2 T& W! s" j. B* H公仔箱論壇11X must be 0 or multiple of 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) V( M2 ?# u" t. m
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM