That is a very simple mathematics question. - R5 x4 l) w& p1 Y2 A9 \公仔箱論壇Let x = Male, y = Female, z = Child 6 ?5 o& _4 w6 L# x- O% z6x + 3y + z/2 = 100 Formula 1 5 f/ P! v7 R: x( I; W2 m公仔箱論壇x + y + z = 100 Formula 2 % K3 j3 |, F v5 S/ ytvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇( N4 V' i2 U8 R2 h# h
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇. p5 `% }6 M5 ]1 N% B
Formula 4 can change into 11x + 5y = 100 Formula 53 t6 ]0 D1 p/ I! d6 \
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇$ r: M' K& ]7 M- Y! Z
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. ( m' ]0 {2 `; i( Z% x5.39.217.76Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children- ]+ r& y. v j+ Y, B% A( L+ I6 }
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
