That is a very simple mathematics question.2 e+ s8 X. L& q* y8 i+ Y$ K
Let x = Male, y = Female, z = Child ; v$ |* n% O: P3 P5 g$ r) i5.39.217.766x + 3y + z/2 = 100 Formula 1公仔箱論壇! C% [3 k5 [0 `0 ]# x u, z" ]9 }
x + y + z = 100 Formula 2 ; [7 {5 T7 {+ Y2 A$ w, D+ _公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3+ a. V' R) b; S- i
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4: q3 E: Y' ]& p$ y% W, H* f! J
Formula 4 can change into 11x + 5y = 100 Formula 5 8 p( m7 f5 d1 M% c7 nTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.1 h% o- |2 z' @3 Z
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇: }) q5 n9 Z2 h6 _
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers