That is a very simple mathematics question.5 U k x$ }' K( A" w( I. d
Let x = Male, y = Female, z = Child( P6 V& _1 r7 G. ~! E
6x + 3y + z/2 = 100 Formula 1 ) v7 Q+ U% T0 }5 ]4 Ex + y + z = 100 Formula 2% v6 y a: N5 k" l
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 / u& o6 a3 {; J3 s- F' x; J; C' GSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4* e+ d( I# `- p/ w- Q
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb6 y; W* R! B5 \& e$ z1 n
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. * K1 j: \9 m9 V" t3 ]% etvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.9 S- {+ e) [+ j
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,childrentvb now,tvbnow,bttvb, c! d# a j$ }. `3 T0 @
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
原帖由 twinsdragon 於 2007-10-13 05:40 PM 發表 tvb now,tvbnow,bttvb* U( x+ y+ K. a e: x" u
11x + 5y = 100 Formula 5
# v$ ?7 r5 [- U5 i5 s: v3 z
11X must be 0 or multiple of 55.39.217.76! k; d! i2 k1 L0 a1 W4 X
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM