That is a very simple mathematics question.tvb now,tvbnow,bttvb% n* o2 R8 _2 D* e* M) A! U$ X
Let x = Male, y = Female, z = Child 9 Y- z/ f% l9 [: z% L# \7 q/ ftvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb" j k! `/ g1 D( i
x + y + z = 100 Formula 2 1 C8 J1 b7 y5 \: [% a; f! @. xtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb# Z8 b& p' M9 v1 P1 g$ I. Y5 l
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 44 @, y* g t7 O
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.761 L( p! R- R% x- K; p
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.; Q7 i9 {8 }+ G: i* w7 D, d3 f
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80., Q3 I) F6 i+ E4 B, @1 s6 t1 O: \
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,childrentvb now,tvbnow,bttvb# E* \: n% g- G+ S3 s7 v9 H5 M
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
原帖由 twinsdragon 於 2007-10-13 05:40 PM 發表 ; ^" s' m& @7 |5.39.217.7611x + 5y = 100 Formula 5
8 y2 R8 B/ B. M& P# e8 ~, Jtvb now,tvbnow,bttvb11X must be 0 or multiple of 5 " k/ q4 ]% O9 I9 m, Mthat meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
86 children s! e" A6 v6 P+ qtvb now,tvbnow,bttvb5 male 1 ^# l8 I; p. [% y) |$ A
9 female作者: dafunhei123 時間: 2007-10-15 10:39 PM
