That is a very simple mathematics question. ( \* R1 q$ Y0 A: P; oLet x = Male, y = Female, z = Child公仔箱論壇; i/ y7 s' g# u, Z
6x + 3y + z/2 = 100 Formula 1 & R( V, C6 v& B% \x + y + z = 100 Formula 28 J$ v6 C3 c; L- L, Y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 ( o3 [: W! }8 j3 ITVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 - K# r! x0 x% c1 \, h/ CFormula 4 can change into 11x + 5y = 100 Formula 5 1 i2 c. @! z, N7 YTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76 p5 O2 x, f1 V/ s* z, R' t
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.$ @1 A* b; @, ]
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
原帖由 twinsdragon 於 2007-10-13 05:40 PM 發表 公仔箱論壇# K. g& I: }% F
11x + 5y = 100 Formula 5
' K) L. U9 \9 H* k) f5.39.217.7611X must be 0 or multiple of 5- q$ Y& h: |3 z9 d9 e- A" x
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
公仔箱論壇# K. g& I: }% F
