That is a very simple mathematics question.3 M4 o' B' c' u6 j( s( Q
Let x = Male, y = Female, z = Child. h/ S3 c1 c: v; H5 U
6x + 3y + z/2 = 100 Formula 1 4 S9 {( F8 I* S+ vtvb now,tvbnow,bttvbx + y + z = 100 Formula 2 : R+ H6 I6 C$ }% KSimplify Formula 2 into z, we get z = 100 - x - y Formula 3 4 i6 W2 Z. Q5 v4 B6 n3 g. ^tvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4- @/ w$ o8 H: t, Y, q {% F! n
Formula 4 can change into 11x + 5y = 100 Formula 53 e3 d* @3 T/ ?0 ]8 {, g
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. ; Q6 d7 w6 R' ?2 A4 W( R& ?2 k公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. & w+ w9 Z/ S+ Y7 D+ n9 Qtvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers