That is a very simple mathematics question.5.39.217.763 G5 t1 O% F; T- }& ]
Let x = Male, y = Female, z = Child9 L5 B4 E1 o3 T! k' T7 z
6x + 3y + z/2 = 100 Formula 1 8 B" d! z/ n @1 ktvb now,tvbnow,bttvbx + y + z = 100 Formula 2* u1 h( Q- H3 D# m) h
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb* T D, b" v; P" X+ r8 l
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 7 w6 K/ s$ a6 M公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.761 {$ f7 R3 {+ w0 ?
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. " c8 b8 E) A8 _3 [6 Z" \- Z4 b2 jAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80." g. b& L' T6 P1 D( f8 E
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,childrentvb now,tvbnow,bttvb0 a' D& m. _5 i T! E) o+ @2 c
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
