1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 $ s) t( Y) F8 P6 G3 R( v- ]3 J! w2 k5 TFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 & f5 J" M' f! f4 J5.39.217.76For 1235.39.217.760 \3 J5 ?: N$ A1 Q0 X; t
1x2+1=3 that is 1 time of 3公仔箱論壇) _* b* b @$ i. V V2 F: v
1x3+1=4 that is 2 times of 2 6 f* ~- b. K x5 n8 e# jTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2x3+1=7 thta is 7 times of 1