1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 6 N9 v& ~% ]2 T: I. v- K, n% N- e公仔箱論壇For 111 would be 1x1+1=2 that is 2 times of 3rd 1: z# m( Q2 g* t( P+ f
For 123 # b1 J; S# T6 B: n& B4 @1x2+1=3 that is 1 time of 3$ R: v' z( B+ t
1x3+1=4 that is 2 times of 2 2 a' D# X8 A: ?7 u! d( M2x3+1=7 thta is 7 times of 1