1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 5 q$ x- Q1 h0 c! p/ P: K7 nFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 ( C; A3 R- g9 o) ?5.39.217.76For 123 5 d7 G2 q5 F, I) g# t7 t& b5.39.217.761x2+1=3 that is 1 time of 3# k7 r# }" x: p8 t8 x8 z5 w' L
1x3+1=4 that is 2 times of 2' u8 f1 g m. @' j+ {
2x3+1=7 thta is 7 times of 1