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第2的....直覺告訴我
0000000000
友華
我已經想很久了' i6 p( C1 G# \7 }) M- I& N/ {
實在太難5.39.217.767 }% L# ]2 o: k+ D2 X( L
只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
, ^) A# V- K$ z! W3 x, K( xassume number 1, 2, 3 and 4, pick number a, b, c and d.
0 E% R0 k( |/ e* G, B公仔箱論壇number 4 knows how many left in the bag which is 100-a-b-c- b& K8 w1 P1 x; w# G! Z# {+ X+ h
take the average of (100-a-b-c)
1 c* q" F; {4 Y4 U2 r' Sthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
4 P4 R. M% G7 Y4 y9 k- L, m* h公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
; g4 P- U) ~1 a9 w" x) r公仔箱論壇so number 4 will have the best chance.
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i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
  r* D8 ?% B8 K. q/ x% Y) O玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!" s/ W8 c2 p! L+ p7 ~

5 h( x, i  Q7 I# \; |9 Ttvb now,tvbnow,bttvb如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                   8 L. a4 W% O8 J3 Z" ]' d# |  H
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             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
. o) @' k4 r/ X2 J5 g4 r" n2 C/ K& Q; [公仔箱論壇So they will all die !!                                                      
, E! V% F2 y( ~) z9 MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5.39.217.761 k& Y1 {9 \1 c  G0 v5 f9 X

/ u/ U0 B2 I! o9 ?( Q" e公仔箱論壇7 J6 k& W$ q6 R2 A$ T+ i% A) U1 g

5 P) \1 ^; L, t' y公仔箱論壇1 y& d% Y- F! `' M2 ?6 ?( E4 |
Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
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Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  tvb now,tvbnow,bttvb! O5 R3 K9 i, ?" e2 M3 M9 u' O
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Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
- X/ u8 ?1 j; f- B, P公仔箱論壇
! d( C% l9 Y, u" ?' r; J5 a#3 did the obvious choice 40 divided by 2 =20, so he picked 20
; r& B# N5 L$ x6 A" MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。公仔箱論壇, p4 f; z& t+ ?4 w# X* r
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
: Q2 o$ N! r, b* @8 ITVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" a  Z4 H1 t4 S( u
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.) O6 r! Z1 i9 M1 g  i/ i$ ?
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Ended all have the same number and all died.
我猜NO4,
1 g2 i6 m8 m* u: R因為他可以取前面三位豆子的平均數,公仔箱論壇" Z4 X0 X& X( r2 F$ n0 h3 m( y' [2 t
也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
1 W4 k; {: c( V1 Y# C5.39.217.76TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ Z  f  }8 E. A. i3 T" u
[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
. [& @: A( e, t( t公仔箱論壇
/ U2 _2 B# k2 _. Ztvb now,tvbnow,bttvb答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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