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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
3 w0 n+ T! r" j( t- Ztvb now,tvbnow,bttvb共四堆
3 T. L7 t  H  ]. _4 U& e9 H6 ^$ T8 o5.39.217.76称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 X* {8 U7 I4 F8 R' B& g
在异常的那一堆中在称一次
. H4 @! h3 _, Z7 y* W+ u- l+ U: j( S  ]5.39.217.76就可以找到了
divde the 12 balls into 3 sets of 4.
, ^% y$ W0 h) E9 e* YTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
( `* z8 w  F3 k: M公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇9 a4 c* N% N  a6 z* Q
if one of the 2 is heavier, then the heavy one is in that set
8 d7 _$ t. n+ g, ^8 Ntvb now,tvbnow,bttvbthen divide the 4 balls into 2.tvb now,tvbnow,bttvb) X1 j8 P/ a9 h% T
weigh them
$ q- i. j6 E" g( p! P/ \and divide the heavier into 1* g5 O9 U( J# |- j
and weight them.
0 p* Y8 {# k9 K$ O5 f9 A8 x0 B公仔箱論壇3 x weighing and get the ans.  
1 _& U+ o6 N, k  K, Q( m" Ztvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.公仔箱論壇1 ~$ E  c1 J1 u* D6 p/ I5 r: A4 v
2. heavier side from (1), 3 aside weight again.
5 m: k4 s$ I' _4 A3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 4 Q1 r1 m4 ?" w. N' i
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" @  c8 J+ L* c7 ~
but i have a question. 重量異常 can be heavier or lighter.... so......
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