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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb( s; y$ V; m/ b5 Z/ }3 u; u0 b
共四堆% _& g7 y* z9 c5 u( E) G
称两次得出异常的在那一堆,其轻重
2 |+ `. k( n. a8 F# j5.39.217.76在异常的那一堆中在称一次
1 k' j7 _) B" M. }8 p就可以找到了
divde the 12 balls into 3 sets of 4. ; m+ H# h/ A0 m
weight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6 ?4 K, V$ r/ c
if the 2 sets are equal, then you know the heavy one is in the third9 W. b6 N! O* X) X. M* B( N
if one of the 2 is heavier, then the heavy one is in that set& F9 f1 z0 b1 Q- K
then divide the 4 balls into 2.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 w9 m. C  H: c# c( V! _
weigh them
& M1 K. F6 j1 I" c: N8 N- r/ z公仔箱論壇and divide the heavier into 10 C2 Q- `9 f8 D' u8 i/ F1 J
and weight them.5.39.217.76% m9 o0 \4 o9 c" d2 `% d) A
3 x weighing and get the ans.  TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ V1 q2 d+ d# c/ M
in less than 15 secs.
1. 6 aside and weight.
( S3 C5 ?6 _6 P4 {2. heavier side from (1), 3 aside weight again.
9 m( M5 M/ |$ A4 r5 T: l0 i3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
) ^* {2 ~6 R; A! A# l
( W8 ]3 P6 V- q5 m6 Lbut i have a question. 重量異常 can be heavier or lighter.... so......
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