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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆. ^- c0 x! S7 X) g) c( b# ?
共四堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# e+ H7 f7 O! b$ w+ ?
称两次得出异常的在那一堆,其轻重
6 n0 G" n! J7 W4 \7 C* U$ z5.39.217.76在异常的那一堆中在称一次tvb now,tvbnow,bttvb( z  j" O4 v& [- o$ h
就可以找到了
divde the 12 balls into 3 sets of 4. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- x# M, L% Z3 j
weight any 2 sets.
: c/ s9 z9 _* n# S; C! J5.39.217.76if the 2 sets are equal, then you know the heavy one is in the third
1 q2 u, A. }, O) D, H* `  j) Bif one of the 2 is heavier, then the heavy one is in that set
0 Z4 r& c) I0 D6 i* S' R5.39.217.76then divide the 4 balls into 2.
' ^1 U5 ~  Y0 J! W) J# M& }7 v  `7 Dweigh them5.39.217.762 W* P" g! g2 k3 K) b/ s$ x9 v  o
and divide the heavier into 1tvb now,tvbnow,bttvb- m. ^, b0 E# l
and weight them.
# C* u# _9 k: F3 M- D# Z- E; `5.39.217.763 x weighing and get the ans.  
4 Q5 b& C2 p. Y) q& R# {/ Min less than 15 secs.
1. 6 aside and weight.5.39.217.76/ _4 X7 X' K4 O* [" C- o1 d- J
2. heavier side from (1), 3 aside weight again.* B6 s" r4 F4 _7 R2 I" m& T3 i
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.765 G3 M; k9 }5 J& L

. ~) ?( s5 ^; {: M0 }7 Q5.39.217.76but i have a question. 重量異常 can be heavier or lighter.... so......
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