返回列表 回復 發帖
答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
4 F6 }$ ~5 {/ J5.39.217.76共四堆5.39.217.765 Z4 _$ J# i% E3 p& P8 m1 |
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb) n3 C7 q% y' I' x
在异常的那一堆中在称一次
" e7 v' ]9 F% C$ N7 I1 _5.39.217.76就可以找到了
divde the 12 balls into 3 sets of 4. 公仔箱論壇7 ?1 o+ n7 t: a4 P
weight any 2 sets.tvb now,tvbnow,bttvb$ |/ `) D+ c" C
if the 2 sets are equal, then you know the heavy one is in the third
0 ]9 c0 U+ b. R6 P1 Y0 Ltvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set
7 k: f& d1 a. W& ~then divide the 4 balls into 2., H1 y4 A/ }  _& y
weigh them
& `! v2 L' N* A* ?and divide the heavier into 1
( N  ^: m+ ]1 r- e0 x1 e6 [; |4 L公仔箱論壇and weight them.
6 ^1 o. R2 b/ h% ?* V  L2 t3 O" x% n* z3 x weighing and get the ans.  
% h8 w5 O8 |1 i' z+ E; GTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.5.39.217.76; w* |: N2 y1 F" q
2. heavier side from (1), 3 aside weight again.
  r! m, F$ |3 @3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- \. m  m+ @" c- L1 Q

# c- }! L& {  l5 N, Z- u1 ^5.39.217.76but i have a question. 重量異常 can be heavier or lighter.... so......
返回列表