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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
* h( x' X% F8 w6 a7 O2 Otvb now,tvbnow,bttvb共四堆
0 {; h) N! r8 x) e& z4 M  p8 qtvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重
$ P5 _5 c" c0 }8 T6 c) O! a0 V* UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。在异常的那一堆中在称一次
6 Z! C$ N7 D( s; D公仔箱論壇就可以找到了
divde the 12 balls into 3 sets of 4. 8 K  i8 W2 X/ @; y# Z. l/ M8 J  m
weight any 2 sets.
( b  J+ G, ^: ^- s. p公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third
. A# p. f8 {( ^% y2 h2 Gtvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set
0 r5 v8 _7 z- {" i5 v0 A& q5.39.217.76then divide the 4 balls into 2.
/ I& u2 ~3 W4 R' L  r. B! {$ H" S4 F2 n6 Nweigh them
6 z1 s1 b" D, a' \2 y9 k9 T& V( gtvb now,tvbnow,bttvband divide the heavier into 1
3 ]5 {0 l+ a, [. rand weight them.8 V- m/ z# ]5 W: C4 F) b
3 x weighing and get the ans.  公仔箱論壇) i/ U0 M4 f8 T% V7 b
in less than 15 secs.
1. 6 aside and weight.
$ O8 E1 a7 {) A! B# n4 A2. heavier side from (1), 3 aside weight again.
( q- J; e# [& G4 E% G/ Z8 Y4 T5.39.217.763. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.76& l& e( S/ S  s2 F' S: X1 k

4 B1 W9 w4 }2 N0 V公仔箱論壇but i have a question. 重量異常 can be heavier or lighter.... so......
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