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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb. U/ Q" @% {! W' P. u
共四堆
' E8 k: a# v. Q! Z6 U5 a7 U( F- Itvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 b  k$ E! @% f1 z9 y9 m
在异常的那一堆中在称一次
) f' I; q9 l1 t$ X: Q! x就可以找到了
divde the 12 balls into 3 sets of 4.
: s9 y# f1 w, a; FTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
* T2 f1 i9 T  a0 {- Q3 T% ?: r/ v5 `5.39.217.76if the 2 sets are equal, then you know the heavy one is in the third
/ J1 D: @( m) p; qTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that set
4 a0 _* g, f' f1 i+ Y. @# K公仔箱論壇then divide the 4 balls into 2.5.39.217.76# P  X. ?9 ~0 f1 p
weigh them
8 l, q/ N) i. K; ~公仔箱論壇and divide the heavier into 18 l( c- G  m0 t4 s. F1 f0 \2 x
and weight them.
5 r! Z( h# M  X- p8 i5.39.217.763 x weighing and get the ans.  
6 Y: E8 g8 o: H5 \4 }) Z公仔箱論壇in less than 15 secs.
1. 6 aside and weight.
  F/ k& i  w! ~. ^2 J  a2. heavier side from (1), 3 aside weight again.
$ q! ~7 k' q7 u" I# Ktvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) D' c! e# C, Z4 X
5.39.217.76( ?# k" m4 j# E8 K( y, J' C
but i have a question. 重量異常 can be heavier or lighter.... so......
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