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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
: d' D& b' o% r, }; R8 D1 f6 |5.39.217.76共四堆tvb now,tvbnow,bttvb) t9 r2 P& m" [: g8 s8 y8 h
称两次得出异常的在那一堆,其轻重
: `: m0 [" Y4 K% GTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。在异常的那一堆中在称一次
; W: U5 A* D" r9 V+ X: Etvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.76# i; x* d. c) N1 z0 f# \- {
weight any 2 sets.tvb now,tvbnow,bttvb5 f! E; x+ Z, i( I
if the 2 sets are equal, then you know the heavy one is in the third
7 n2 {7 s& M4 J* W  b( gTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb+ u! ~) K: z7 f3 F: Q& e
then divide the 4 balls into 2.2 w( B- U2 H  x3 z6 l7 B* T
weigh them
: `8 I, v- e. [1 T8 _# }5.39.217.76and divide the heavier into 1公仔箱論壇$ m+ d1 r& z8 z7 W" e
and weight them.
% B2 z$ b2 M3 R3 x weighing and get the ans.  TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 j  b5 R- |- \7 B9 ]+ E
in less than 15 secs.
1. 6 aside and weight.
1 R/ L* ^% a7 k1 M* ~1 `tvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.公仔箱論壇; {: e2 D$ W2 [) o+ x
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
6 m6 Y2 w4 v+ s7 [1 l# t, Q5.39.217.76tvb now,tvbnow,bttvb( T, ~( f' w' D, F! f+ A" x" n- T
but i have a question. 重量異常 can be heavier or lighter.... so......
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