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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆% |! _# h: Z" H% e3 @* F  y
共四堆+ u; r6 H2 t! D% `( p! \
称两次得出异常的在那一堆,其轻重公仔箱論壇7 k4 k: R* j9 [9 L
在异常的那一堆中在称一次
. O- p0 ~4 E7 q3 ]& U1 V- Q就可以找到了
divde the 12 balls into 3 sets of 4.
; t' u# z! ^( k/ Atvb now,tvbnow,bttvbweight any 2 sets.
6 R$ l: a5 M: ~$ u) vif the 2 sets are equal, then you know the heavy one is in the third
. {* P( d5 M! v/ b, wif one of the 2 is heavier, then the heavy one is in that set
; j' i6 m+ Z- cTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。then divide the 4 balls into 2.
4 G  r8 L/ Z/ zTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weigh them
4 t  Q$ A2 ]* k' g; z" ^: g( `! Q6 land divide the heavier into 1
4 R" \; Z6 g. s  \* k% @& _公仔箱論壇and weight them.3 y% d+ t! M$ d3 m8 \
3 x weighing and get the ans.  
/ Y& j8 f$ o& q8 Y' i7 ?, r4 `in less than 15 secs.
1. 6 aside and weight.
$ i9 R- H+ V* f2. heavier side from (1), 3 aside weight again.8 D5 L& D  s, i
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. tvb now,tvbnow,bttvb: l$ h+ G' R" r8 q! R

' h7 a; S2 U9 M6 stvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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