1 - compare 4 with 4: C$ m( k) \4 o* ~( ]7 Q' U
if (4v4)= same that means the rest of 4 is got more weight
2 Y. B7 V* N, m7 V1 x5 u5.39.217.76 then goto 2 - compare rest of(4) - 2 with 2
$ X" V# [# P+ ]0 y5 \ `) P if (left side is more weight)
7 X( U+ g6 J. W& N8 }: y2 @- ztvb now,tvbnow,bttvb then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
* {' j* d3 X6 c4 h! }; a3 y5.39.217.76 else ( right side is more weight)tvb now,tvbnow,bttvb+ @5 x$ g* b- E/ G6 |
then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
! n/ T1 _ U, Eelse ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
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