zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
* \. }: y4 N# `% ~- M. P7 K, X将比较重的那份再平均分成两份成一次- X; Q* r/ H; f
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
) g/ G9 E6 t4 V" u2 X5 dif  (4v4)= same that means the rest of 4 is got more weight$ \2 g0 Y3 _' b, p: r
    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb# X1 X& K! X) H1 c' L: L  y
           if (left side is more weight)公仔箱論壇: H7 H7 r2 p% h; A$ K3 k
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
( z( d7 U; O, C% C4 F# k          else ( right side is more weight)) `! k6 p; I3 e7 K
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
$ P' g% J% {0 b- |; Q& h- ?公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。