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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次5.39.217.760 R, E3 s. _/ D8 }* k' c; h
将比较重的那份再平均分成两份成一次
& a: ]& S1 J, Y3 y剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 45.39.217.768 \1 ]8 _6 m+ j3 r1 A$ i/ m0 h! H4 M
if  (4v4)= same that means the rest of 4 is got more weight
9 |1 x7 |. c& ?$ h3 Etvb now,tvbnow,bttvb    then goto 2 - compare rest of(4)  - 2 with 2
8 M8 i% O+ q! h0 Z6 T) T1 u& t7 _           if (left side is more weight)公仔箱論壇9 \) a* c: u' U$ ]
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
. O% z1 j7 H1 K0 v, F1 U5.39.217.76          else ( right side is more weight)公仔箱論壇7 w8 e' f; a4 x4 P7 }
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
9 B+ Q. z6 s9 B5 V  Q% n/ F5.39.217.76else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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