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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
, b) _# R- p8 R9 H+ q. {5 h6 ~将比较重的那份再平均分成两份成一次7 V, V5 F$ y" N# ^
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
, @7 g8 j' {; r2 g8 k5.39.217.76if  (4v4)= same that means the rest of 4 is got more weight
2 [, }( P: w: Y    then goto 2 - compare rest of(4)  - 2 with 2
, d$ a1 b' i& z& m, [: }公仔箱論壇           if (left side is more weight)TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  L% F; @5 d+ k1 i9 Y5 H. K
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer; G1 X9 u8 y+ u
          else ( right side is more weight)
  {/ H, J4 ~% v6 Y: F2 otvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
# p; `% s% i7 D0 x: c2 m% D公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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