zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次3 \# {  b0 u0 J1 A, B! ~+ v
将比较重的那份再平均分成两份成一次5.39.217.76) j3 v2 c! W' m+ t5 ]
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
/ f& l  f% }5 s/ `5.39.217.76if  (4v4)= same that means the rest of 4 is got more weight
# d+ r7 x5 e, `+ \6 `* [    then goto 2 - compare rest of(4)  - 2 with 2 : T3 d: d/ N2 V& L/ P
           if (left side is more weight)# g3 g% f, q6 c) w3 ^# f
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb. c6 C6 M0 n5 |3 u- Y
          else ( right side is more weight)tvb now,tvbnow,bttvb4 X" Q6 Y$ X" m, Q! t$ E4 Z4 r' X' z
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answerTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' E8 L  c! a1 h" u- q$ v
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。