返回列表 回復 發帖
see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次5.39.217.768 v0 R; q& Q2 }2 @3 B
将比较重的那份再平均分成两份成一次
0 c. f1 n" L! p3 x" t$ _2 etvb now,tvbnow,bttvb剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4tvb now,tvbnow,bttvb+ `& `" i* r9 i- q* T
if  (4v4)= same that means the rest of 4 is got more weight
# T# A  n: `; H: K! f# z    then goto 2 - compare rest of(4)  - 2 with 2 ' c. F6 ]7 z; I9 I! U
           if (left side is more weight)
* z4 s# N1 a2 n: ?& ?              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb8 Z0 h6 D+ I" u9 x) Q, C/ D
          else ( right side is more weight)公仔箱論壇. o5 T# y8 j0 @; w
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
0 R1 R. L3 `  |4 x4 A8 Z9 welse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
返回列表