Exactly, done in less than 10 seconds, not sure why the host make it so complicated, he/she must have misunderstood the original question before posting.tvb now,tvbnow,bttvb/ q$ I9 B# d1 Q3 I# @& v7 K y
8 [' A( Q6 u P. D' S7 ztvb now,tvbnow,bttvbStart with 12 balls, weight 6 - 6 on scale, the take the 6 from the heavier side and weight 3 - 3, then take the 2 out of 3 from the heavier side weight again, if these 2 balances then the heaviest ball is the remaining 1. (please oh please don't ask what happens if these 2 our of 3 does not balance). |