Exactly, done in less than 10 seconds, not sure why the host make it so complicated, he/she must have misunderstood the original question before posting.5.39.217.762 e k# J8 `/ C7 J7 p T* h
5.39.217.763 C$ y( z$ V+ V1 p5 Y
Start with 12 balls, weight 6 - 6 on scale, the take the 6 from the heavier side and weight 3 - 3, then take the 2 out of 3 from the heavier side weight again, if these 2 balances then the heaviest ball is the remaining 1. (please oh please don't ask what happens if these 2 our of 3 does not balance). |
發表於 2009-4-19 08:53 PM
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