this is too easy!!
5 L! X! j) u4 a1 r% O9 X9 u5.39.217.76% H3 T, z( n% X9 u& I! y0 x
1. put 6 at each side.. take the one side which is heavier5 ~0 y0 o% A( O- v; c
2. put 3 at each side.. also take the heavier side
$ Q4 H# Q, V, i8 V( i- }3. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball.. |
發表於 2009-1-7 05:31 AM
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