Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group.tvb now,tvbnow,bttvb' x: a& y; m$ b) \6 m. B! y
The problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once.
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