yeelam_168

好難呀:onion14:

chia87

see answer

jay123

Thx thx

shin0_life

阿斯打双打搭档

iio5

thanks:024:

satoushi

:onion31: ;川

tcmhw

divide 12 into 6 one side n balance it..
4 c3 M7 K3 x& g+ [' \5 k. O( i5.39.217.76den take da heavier side which is 6 n divide into 2 parts again..5.39.217.76% J1 S3 {5 h5 C3 _3 o
3 one side n another 3 another side..5.39.217.76; G" ~3 m- m3 G& U
den u take da heavier part again..
, E* \; s  {' K: p0 L" e5.39.217.76now u left 3 pingpong.. u can simply choose 2 of it n balance again../ i% d/ X% {* r5 G. }% a
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan

umc8800

thank you

giggs8171

so easy... 1minute can get it already...keke:onion05: :onion05:

yummyyummy123

ok啦~~~~~~~~~~

kkhc

Let's see if I got it right.

thomas_ngan

haha?:sleeps:

jw324

多謝分享

bintang118

seeee

如果可以

let's see