hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
* a! P* `7 E2 c2 W" m  d' w) o% U1st u divide the ball into two group (i group 6 ball)
! a. X% h! u/ _, W5.39.217.76then 称 them c which side is the heavy 公仔箱論壇1 O& w# H7 H$ V0 ^4 R# U; W
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
5 }# p4 r7 f* P- q% e- T  Jif not balance take the heavy and then ; {( j7 }# V3 `
take the heavy group divided into 2 group i group contain 1 ball than 称 it
8 c9 i# I0 F/ m+ A6 W& Xthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb# C; R, J, B- U$ l* V) {- F: P. Y
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
1 Z6 }0 A* y7 F# |% O然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me