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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
2 T! F7 A6 b0 ]& d! e5.39.217.761st u divide the ball into two group (i group 6 ball)tvb now,tvbnow,bttvb! E) f# n/ q3 ]! l( z# L" G1 X
then 称 them c which side is the heavy 公仔箱論壇- n: X/ W) ~7 k
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
" y6 H$ j* l: @" s( k( hif not balance take the heavy and then tvb now,tvbnow,bttvb9 w$ x4 |; G9 l! y9 y  S) h
take the heavy group divided into 2 group i group contain 1 ball than 称 it 5.39.217.76- k& G5 r) L5 a  @8 R$ f
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb* s' z! W) D9 {4 X
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
  t3 v  Z( R& S3 e: w' PTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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