hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^" g+ J/ x' M3 Z+ C+ z6 N" k& {
1st u divide the ball into two group (i group 6 ball): Z" E; v0 m& m) X5 n
then 称 them c which side is the heavy
' V+ X3 F7 r% n5.39.217.76then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
, N: c$ v+ m0 z( }if not balance take the heavy and then 7 h+ B! T* U7 V' c, h5 R
take the heavy group divided into 2 group i group contain 1 ball than 称 it
1 _  {. F$ [- e$ S! x$ E/ P7 athan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
  ]. `! c9 @' b7 }TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边; t  {  Y* ~! ?+ U2 [. L
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me