hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
* a+ W& w( X* M0 W4 j3 t5 y1st u divide the ball into two group (i group 6 ball)
1 n4 G( R" U$ d9 L. U5 q  G8 o/ Wthen 称 them c which side is the heavy tvb now,tvbnow,bttvb, b0 B, v5 `( a" z( ~
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group / T+ M9 W; J5 \1 K- `
if not balance take the heavy and then 公仔箱論壇! T. {  }' U: r3 D4 j2 y, G8 X
take the heavy group divided into 2 group i group contain 1 ball than 称 it
: d4 M" M# {& h0 `4 c1 w# U1 A$ [tvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb7 ]+ d6 J7 ~5 \' n
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边. D# }& C3 W& A% I
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me