hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb$ F- l( y- p) t/ p
1st u divide the ball into two group (i group 6 ball)
/ E6 i2 Z* l3 \" b! ]3 \* @5.39.217.76then 称 them c which side is the heavy
7 }3 U6 L7 z- S/ Y5 wthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
2 S$ r9 ^/ G4 h1 g$ c; Z& _/ `if not balance take the heavy and then , w* f' N" N  `9 \
take the heavy group divided into 2 group i group contain 1 ball than 称 it
+ l, K+ w3 J% `8 Pthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb, L. e* U+ u+ E
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边4 A0 n- m4 k- ]4 Y
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me