hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
& C5 a0 Z1 A8 C5 R/ f# d9 a' s1 k0 z1st u divide the ball into two group (i group 6 ball)
5 ?* v4 c7 a4 w4 G5 u1 ]6 wthen 称 them c which side is the heavy 5.39.217.76! r7 x6 y- J& }' D2 R: |, y
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 6 E) [% e8 C* n
if not balance take the heavy and then   ^6 J% J6 ?: K' F2 h( K$ q7 k
take the heavy group divided into 2 group i group contain 1 ball than 称 it
& }; f! G$ ~" _% |1 h2 Xthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: $ M, R4 X" Q2 z% Q3 V
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
; S- B# E/ ]0 @+ F+ W/ P然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me