hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5 Q5 v0 }- U9 A0 |) O6 K5 n
1st u divide the ball into two group (i group 6 ball)
2 t: z( y" G8 L- K  A( N+ s. stvb now,tvbnow,bttvbthen 称 them c which side is the heavy tvb now,tvbnow,bttvb" W/ t3 S1 E# a  W  a# u
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
$ e' x+ j  U, O6 D' M8 k公仔箱論壇if not balance take the heavy and then
2 N; N3 L- g. ~! d" qtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it 公仔箱論壇7 L3 I9 |+ f6 P+ R) `1 f3 r5 ]3 S
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb  v. r2 i( W; z. V
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
) J( V2 y* l. X8 c然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me