hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
+ p$ ^( K# y0 ~" H* `公仔箱論壇1st u divide the ball into two group (i group 6 ball)5.39.217.76: E/ T! Z( U. ^$ f. I
then 称 them c which side is the heavy 8 i7 o4 _( m- T1 [% I3 o) Q
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
. J9 k0 u7 A4 I4 r! E) jif not balance take the heavy and then
9 w9 o! l# P  p: N6 K* z) ~0 F% @6 Q0 T公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it 7 n$ S- B. a( C) J
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
, C1 l) t, [& T（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇4 r- f7 x0 l+ c' @; ~& {
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me