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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
( g8 y: _5 S) Q  e1 E) D" Ltvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)
: N0 Y! ]6 g$ Y# f* }5 @then 称 them c which side is the heavy tvb now,tvbnow,bttvb; @. ?% f0 R1 _$ y% N6 ~% K* z5 a
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group ; g  R4 g% x6 m, s5 ^# T
if not balance take the heavy and then
6 b2 C# r" @: a& l) o+ m5.39.217.76take the heavy group divided into 2 group i group contain 1 ball than 称 it 8 q; Q' \' E8 W
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb5 M1 _5 w3 z+ ?& B# R
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- v7 h& S, t* B* n* Z1 C0 K8 j
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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