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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
0 _4 K; ]2 U! @+ l; q2 E  i5 b' Q5.39.217.761st u divide the ball into two group (i group 6 ball)公仔箱論壇/ G3 v" U& b5 M! u# ?  j$ v# H( {6 B
then 称 them c which side is the heavy " O. X4 e: k8 ~3 i' z& a
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb) Y' f9 F* j: [3 X7 G0 h; A- A0 m/ y
if not balance take the heavy and then % G( y# A. P6 x0 Z# Q' A
take the heavy group divided into 2 group i group contain 1 ball than 称 it 5.39.217.768 k# y6 b0 `$ r( @+ O% j" ?5 K
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
3 h( w2 A/ a$ ^) b. f" {2 l5.39.217.76(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
% v  j+ S; [" Q) L5 ?tvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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