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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^2 @+ ^( \7 S5 h
1st u divide the ball into two group (i group 6 ball)
: Y, Z/ i: J. m; ^then 称 them c which side is the heavy tvb now,tvbnow,bttvb% y9 Q$ v# a/ d1 V% h* r& R' C
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb, r3 W' y" o, p& p. O
if not balance take the heavy and then 公仔箱論壇6 a+ t) E/ M7 w
take the heavy group divided into 2 group i group contain 1 ball than 称 it TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ N1 K3 O9 o2 m% `% F
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 9 i7 g8 Z0 d0 {) Y4 ~
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇4 x' g7 D1 t7 j' j7 M& h
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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