hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5 p4 s: }3 _) w
1st u divide the ball into two group (i group 6 ball)
' ^6 R# ~! p0 P2 r; `% S- `then 称 them c which side is the heavy
3 u4 B& q2 P, w5.39.217.76then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group $ f2 Q" C- G1 v  ?& D5 x
if not balance take the heavy and then 5.39.217.76, K3 ]; J5 E& P$ B5 L2 b7 B, s
take the heavy group divided into 2 group i group contain 1 ball than 称 it
; C4 U4 V. `6 T  Z公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇( i1 K' s, q- ^) y
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边" X7 f, D3 D! s+ l6 {1 ^) R+ ?/ k
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me