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[IQ題] 2 Math related IQ problems

I just read these last week.  I hope these are new in here.
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#1)  What is the next sequence?tvb now,tvbnow,bttvb; T) g/ W4 F# [4 a0 K/ ~2 E
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     1, 11, 21, 1211, 111221,  ????5.39.217.765 X2 r5 p# Q) V' @3 q# w

: M: F' J9 c9 e* k: G' F# O0 i% ~( ~#2)tvb now,tvbnow,bttvb: N* A8 U( w* M3 \
tvb now,tvbnow,bttvb8 }, E" q1 Y5 @! g5 q/ A3 J7 y
     3129 = 1* Q- A  S( ]: B* d
     2581 = 2
4 i  g9 [0 N4 c+ `7 y) B1 V% d7 B1 Ntvb now,tvbnow,bttvb     1111 = 05.39.217.769 d0 u% V6 C+ ^2 }
     5983 = 3tvb now,tvbnow,bttvb8 q0 `  n" F! h/ c; r  D( \
     6730 = 2
& s" a' _* x  c' [6 {TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。     9735 = 1
0 E& @6 y0 w# F9 [1 t/ U1 ETVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。     6666 = 4; b3 B  U! z% q8 B5 m
     8136 = ?tvb now,tvbnow,bttvb% ?* Q1 L5 I) R+ e

& T8 q* [8 S8 s: G4 Q公仔箱論壇
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% G3 h" f4 z) l  \  o0 rTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Answer will be posted 4/15
#1)312211
8136=3
dunno ah
The numbers in this series describe how the previous number is formed.
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4 \& I8 o0 K+ z6 t- j6 Y* l' hThe first no. is 1
! y7 P1 `3 m0 i" e3 W( SThe  next one describe it: there is only one "1", therefore 11
7 V6 r' b# d3 _  z, Y% w+ ~5.39.217.76The next one describe the "11" as there are two "1", therefore 21
$ u7 v; |7 S% r) l: O公仔箱論壇The next one describe the "21" as there are one "2" and one "1", therefore 1211! n& \1 Y* [  i' a% ~6 {. R- F
The next one describe the "1211" as there are one "1", one "2" and two "1", so 111221
( a7 d! Z" _: mThe next one describe this "111221" is three "1", two "2" and one "1" so the answer is:
  I% ?( {' [) f$ r1 p, k) H5.39.217.76312211
- R, v, R% G) p4 ?7 D& k1 |tvb now,tvbnow,bttvb
' h: F% N7 z, D* H  |公仔箱論壇I give up on question two.
question 2 answer unavailable
本帖最後由 gm3stevens 於 2012-6-23 06:56 PM 編輯
. f' C5 \' Z' H$ d0 v$ B# h+ R* ]4 Z% p5.39.217.76
* s! Z; H$ A! m7 \- c" m& _# ?After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right.4 Y. f& c% J; e6 m. F  u# j
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So the right hand side number 0 can be represented by number 1 tvb now,tvbnow,bttvb1 r& ]7 x. _. P% k8 Z" k2 S" a$ y
The right hand side number 1 can be represented by 3,1,2,9,7,5tvb now,tvbnow,bttvb0 X  }$ ~: q1 J; ]3 r4 w. M. d
The right hand side number 2 can be represented by 2,5,8,1,6,7,3,0' Z7 X* ^1 c$ U" o) F
The right hand side number 3 can be represented by 5,9,8,3
/ _9 s# m( b1 q6 n& b, U. gThe right hand side number 4 can be represented by 6' ~8 ~' P. _  e7 J; a
Now the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 2
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Sorry. My bad. Someone told me that it is actually counting the number of holes in the given number. 5.39.217.76/ O, P5 h  H- p+ i7 c
There are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3.
5 Y. \! N1 Q$ d5 y0 gtvb now,tvbnow,bttvb
: W9 T! Z7 B4 h) c0 R5.39.217.766 Z: k5 |  _: H( u- t
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