That is a very simple mathematics question.
: R `. ^3 g0 L, d' w2 @Let x = Male, y = Female, z = Child
; `" V1 f7 w* ?TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1" T' q" U" a- w, m4 R2 N) {! i. V
x + y + z = 100 Formula 2
4 R6 A& L9 k* H; l2 VSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
+ Z. G5 \: s! l+ s- _+ t6 VSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb1 m2 ~8 X$ A a4 u% i$ j
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇! C! O) q: I" _
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
! A+ g2 p2 E$ atvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
5 W2 T/ S7 L% v% M9 F2 Z5.39.217.76Eventually, the answer is 20 female and 80 children and no male. |