That is a very simple mathematics question.
! {# O( R$ W' Gtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child
: l4 c* v( R( D& Jtvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 18 q( b' U+ ]6 H1 `
x + y + z = 100 Formula 2
( W' g) x, `8 F% ~' Z( Q- h# o' N8 `tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.76* z0 f5 o* W3 J, c6 |3 {/ Z
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4/ s) x1 d+ R8 B% ]8 o: x2 Y# j
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76: I# f8 K* }" }, _
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇1 X) C0 q+ C- g3 I; j) |6 m6 b! Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
, H- X _: T5 d6 l; h2 p) uEventually, the answer is 20 female and 80 children and no male. |