That is a very simple mathematics question.
. m' q$ f$ F3 dtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child5.39.217.76# D$ g7 O. U" D! U1 B& x
6x + 3y + z/2 = 100 Formula 15.39.217.76 {# Z; I0 r$ h; b
x + y + z = 100 Formula 2
$ ?' \; X3 u4 `0 w9 M& @0 O公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
- r! }2 D" y3 }8 m) M% [0 x5.39.217.76Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 46 D+ ~& K# S9 e7 C' ]9 [
Formula 4 can change into 11x + 5y = 100 Formula 5
$ S* Q2 V: E; g, t, Q5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb; z3 T1 t t0 j
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
; t7 D" V9 F8 B3 U: Y, Y公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |