That is a very simple mathematics question.
" `0 a: p3 w# l6 ? D# M5.39.217.76Let x = Male, y = Female, z = Child公仔箱論壇; n1 ^; K9 A3 B; s1 e8 p2 x% g( q
6x + 3y + z/2 = 100 Formula 1
) X6 r. s- _: h3 {8 Gx + y + z = 100 Formula 2
1 J4 ]. Q3 N& ^" o5 G5 [1 _5 A5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
: @: A8 s8 p; t: F. [+ }" f公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4, l; L0 B/ {; \ |6 K( ~$ n+ b/ Q
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76! w) D. a; }/ }4 F) A
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
0 k* o) ]; A5 A$ k% L, D7 D) x% }And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
& `+ x. t: g; D1 M/ ]公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |