That is a very simple mathematics question.
1 K, T h3 ?+ J+ L2 H) B& kLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 c4 U) A2 U0 v$ U+ ~
6x + 3y + z/2 = 100 Formula 1
2 ]; m( o5 E) S5.39.217.76x + y + z = 100 Formula 2
, \* U$ x4 C% k3 Z4 w0 Z' u5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
7 _. ?1 Z6 c8 G) p5 e' y) r3 DTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4/ _5 q& e$ `+ V6 O/ |, u
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76' U1 ?2 A s: U3 j" I/ q
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.764 W* \/ M3 B& P0 g9 U0 l
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ q: |1 r3 h) F
Eventually, the answer is 20 female and 80 children and no male. |