That is a very simple mathematics question.
9 _! T2 U/ `. E# F: vtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child
5 W% b* j0 g. L# B) ?6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb# _0 }. ~3 r% Z) j- x* d
x + y + z = 100 Formula 2
" K9 R3 o) f' a6 D4 m5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
2 r- W+ }8 l( ltvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
& @1 j, q$ F* H MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb0 D7 ~) ?( B9 K; z
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76/ w: R: |' |* B% e# W
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
; M# Q4 {( z o2 vTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |