That is a very simple mathematics question.
1 L$ Q4 s0 V+ k) i" D. J" z G/ VLet x = Male, y = Female, z = Child6 n+ \% t2 ]) f$ O1 ~
6x + 3y + z/2 = 100 Formula 15.39.217.76$ B; m1 t; R0 N# g% g' ]
x + y + z = 100 Formula 21 V: Y) r! G( d, q6 n+ Y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
9 j* G# k3 d2 c. e1 t; gSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
5 j; U2 T* U/ v- S公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
) S% a m9 B: W7 Z0 Q- d7 PIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
. O4 m. M0 f6 t! ^( K0 e+ hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
# J1 e3 ]9 x1 y- `" TEventually, the answer is 20 female and 80 children and no male. |