That is a very simple mathematics question.
+ R( H+ B+ M& L) U3 WLet x = Male, y = Female, z = Child4 t. n$ Y2 b; a# v! e2 P
6x + 3y + z/2 = 100 Formula 1
8 m, C: l) R# Z8 qx + y + z = 100 Formula 2( a: ?1 e/ B/ U1 h" K. z
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb2 F8 T i) g) {
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 42 t+ Y5 E5 B6 O" Y
Formula 4 can change into 11x + 5y = 100 Formula 5
# _$ P% R9 l6 T( eIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb, s Y* `4 @, a" N
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ B5 o5 D/ B3 f
Eventually, the answer is 20 female and 80 children and no male. |