That is a very simple mathematics question.
$ M* l9 I t4 C% b1 z; cLet x = Male, y = Female, z = Child公仔箱論壇5 d+ _( e3 t% D/ }# Y# A1 I8 h& f
6x + 3y + z/2 = 100 Formula 1
, l5 Q$ Z' r; d5.39.217.76x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。( R# M- y& F# U) e# ?! K, Y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3- K# N; e0 S9 X" |8 \
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
; a1 _ N- h3 l( ^5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5
1 X* F$ ?4 g" I: KIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
) V- p; P! s0 B5 S+ g5 o3 dtvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
3 Z' w1 N# b! ~; v5.39.217.76Eventually, the answer is 20 female and 80 children and no male. |