That is a very simple mathematics question.
" q2 t& Z; t/ y: DTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child公仔箱論壇% F3 x1 q, s8 W8 P; Y1 d
6x + 3y + z/2 = 100 Formula 1
, L; K6 Y' d" q公仔箱論壇x + y + z = 100 Formula 2公仔箱論壇1 F. q. b5 _& Q
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3% ^" V3 i5 j0 y. Z
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
% N, S5 ~' p! b3 [. m) e+ w. k) s5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76) C% p+ R' J* E- Q7 S7 c
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76; n/ h+ q, b- _0 @
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
1 j! I3 y0 B! N9 STVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |