That is a very simple mathematics question.
6 ~! J! U" C/ w4 Z& {: Atvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child5.39.217.76 Z$ m, j& e4 ~
6x + 3y + z/2 = 100 Formula 1
( h/ i% s u, U% J6 X5 v; itvb now,tvbnow,bttvbx + y + z = 100 Formula 2
7 K a/ x; c4 f) A# B; T# XTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
. a) I) {0 T9 m3 y" sSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
5 o& h6 T s/ A3 w5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5
: F% t1 [ B, oIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
3 j$ c% E3 B7 ^/ e0 _公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
, R1 u1 v5 ^6 g5 xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |