28 students are badminton club members only.
, p( e; E) y% R8 Q+ {) itvb now,tvbnow,bttvb: B$ p* r! B9 j; z
2 students are in computer club only.
) b2 o: e6 q ]5.39.217.765.39.217.76( A1 E1 f) {$ H, p1 K5 @1 c
12 students are in both badminton and computer club.5.39.217.766 z- v: @9 V0 ^' w
3 {- j2 w2 |3 h* ~
therefore 28+2+12+6=48 |