1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 2 v7 s. ^) ?# W) E) t, E: v7 `5.39.217.76For 111 would be 1x1+1=2 that is 2 times of 3rd 1 : T& v- @# W+ N/ X# @! }. ZFor 123 : m) A! _! X1 o. g9 n+ O5.39.217.761x2+1=3 that is 1 time of 3 ' E& C1 R6 Z& b T. ^1x3+1=4 that is 2 times of 2公仔箱論壇0 K2 C) c6 b7 W! k5 t0 Q! E" A
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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