1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 1239 |0 U6 k& m$ s
For 111 would be 1x1+1=2 that is 2 times of 3rd 14 e3 \2 u1 s- C$ e
For 123 7 X A4 v! v. J; s) V4 l公仔箱論壇1x2+1=3 that is 1 time of 3 $ n# U8 i2 j0 E0 J$ w z8 XTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。1x3+1=4 that is 2 times of 2 5 x$ P5 b5 U3 r2 S. dTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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