1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 $ D* t0 I' r4 M* _9 v" L3 ?, uFor 111 would be 1x1+1=2 that is 2 times of 3rd 1, @+ b1 u) H; }+ n4 d) M6 M
For 123 3 r- j3 E6 X7 g2 ^TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。1x2+1=3 that is 1 time of 3 - F+ G2 T) N) n0 O1 U2 B) g1x3+1=4 that is 2 times of 25.39.217.76 c4 s) ~8 E+ m& f# \
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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