That is a very simple mathematics question.
4 b, |3 \- I4 y公仔箱論壇Let x = Male, y = Female, z = Child$ H4 s9 ]* x f7 m3 o& T
6x + 3y + z/2 = 100 Formula 1
9 ^4 C1 M; u5 N& P, O9 q% atvb now,tvbnow,bttvbx + y + z = 100 Formula 2tvb now,tvbnow,bttvb$ O/ w9 z$ H% s8 H( u& u# Y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
' W2 G0 Y, ~ A, V, ^2 _% S' {$ L. X5.39.217.76Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
& [ a* C% v. r& }& G3 VTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5. Z6 y# h9 a: _/ U. `- @
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
" f: [; \; u5 ^) t+ z公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.76* k! v) W: |: s0 Y$ _% l
Eventually, the answer is 20 female and 80 children and no male. |