That is a very simple mathematics question.
: I# U9 a( \& T9 JLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 s! X. {* B4 h3 V3 ]' E5 e3 H
6x + 3y + z/2 = 100 Formula 1
% x1 L% ~& w, |' o7 atvb now,tvbnow,bttvbx + y + z = 100 Formula 2tvb now,tvbnow,bttvb a) C" V4 r% v
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇$ t5 d2 \/ c' I$ e; z" n
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇& `6 y$ C! w7 x. q% \
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇" z' n, I; M4 O2 X( [
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
/ Z0 S) i5 Z# A- w! P4 `TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.76 Y( T; W& e6 y, c/ l/ }
Eventually, the answer is 20 female and 80 children and no male. |