That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) R) |4 P6 z8 U+ ^: P8 U' f
Let x = Male, y = Female, z = Child5.39.217.769 N; Y8 S5 Q1 l0 W* s
6x + 3y + z/2 = 100 Formula 1
5 v; O; F8 r5 J$ t( E5 ^+ Itvb now,tvbnow,bttvbx + y + z = 100 Formula 2
. b7 `$ e* A s6 W5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb) k. @* G$ b6 G" T- {
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
. O2 t7 R N z7 M' L [+ o公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
f1 S# W! O2 S5 A; b# p5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.765 Q- N2 y/ S c' n; d. J0 a
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 ]; o. U; t# f
Eventually, the answer is 20 female and 80 children and no male. |