That is a very simple mathematics question.
- W1 }) ?, N3 w" `8 z7 _1 WLet x = Male, y = Female, z = Child
8 o3 q) Q6 b5 {! tTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1
7 K% B( Z" z( D0 F( _x + y + z = 100 Formula 25.39.217.76) b5 n! h) q* b3 t% [
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
. N6 a. r8 q, v8 Y* E; L2 Q公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ _1 Y, o# f) uFormula 4 can change into 11x + 5y = 100 Formula 53 i) |7 m& r1 w8 Y; s
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 s' @2 b5 U' B公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇, |* v5 i/ G {( l& a
Eventually, the answer is 20 female and 80 children and no male. |