That is a very simple mathematics question.tvb now,tvbnow,bttvb3 m- \( E/ j; }+ ]
Let x = Male, y = Female, z = Child公仔箱論壇4 `6 `6 Z" v5 C1 z+ N
6x + 3y + z/2 = 100 Formula 1
# ]2 g7 X8 f" z% x& @6 C* g5.39.217.76x + y + z = 100 Formula 2
4 ?* c4 p3 C: Y! T; ~tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
, n+ h* K& G! E: J0 ~. B& ySub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇! N; ~. P1 @* X8 t
Formula 4 can change into 11x + 5y = 100 Formula 5
" |- k7 B9 X1 t5 a& `tvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
3 ~& ]: R2 b" O7 [" O7 XAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.: N. _' S# v' Q) ^) L
Eventually, the answer is 20 female and 80 children and no male. |