That is a very simple mathematics question.
7 r" U- @1 _ b3 WLet x = Male, y = Female, z = Child
+ e' d" _4 |( F& C+ o+ N5 B6x + 3y + z/2 = 100 Formula 10 v( J" K& y' _: ~9 X
x + y + z = 100 Formula 2
) a! L1 x; I( ?4 U5 o+ P8 z公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
! j& l! |5 C! T8 k- utvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4" r# w0 G% d- z! x
Formula 4 can change into 11x + 5y = 100 Formula 5) [+ G6 V$ ~% E5 J7 l2 b7 w
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb9 v# a9 y: j3 R2 I! _
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 a( W, Z3 y, D( s8 ]
Eventually, the answer is 20 female and 80 children and no male. |