That is a very simple mathematics question.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。) X2 E' X4 }' Y0 Z. b' x: Y
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb' h' c2 `4 }( \* a8 d3 s$ e
6x + 3y + z/2 = 100 Formula 1公仔箱論壇6 z4 Z. H" D0 A+ m% s
x + y + z = 100 Formula 2公仔箱論壇" D: {2 c. ]. \4 `$ \) s
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb: K2 |* P8 O2 x; I O
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4/ s8 s) u( s% o' L i$ O' [
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇; T b! t3 m9 E3 L- A8 P5 `* x
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇4 ~/ z, a7 `4 E4 T2 j0 O
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇: `! Y" w# A+ i$ Z3 k
Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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