That is a very simple mathematics question.
$ \* c8 x' \* e8 t/ uLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" k& o) Z3 K1 F; ]; @' J& @' m7 o
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb3 C5 k- N' V. `+ Y( g3 Z8 W
x + y + z = 100 Formula 2tvb now,tvbnow,bttvb2 w7 P2 |& a% r- e+ Z
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.763 [5 ?7 p, \9 _1 `1 I. p! C
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
, ~. F6 J1 V, w8 Q% H& W3 ?公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
! x4 [9 Y& [4 h. _4 T, u" zIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: m% ~0 E5 M0 _2 u. s( B. C
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.# m8 t& V- [) N, G0 G) n4 ^- n
Eventually, the answer is 20 female and 80 children and no male. |