That is a very simple mathematics question.5 R& a5 p) w7 E" U4 E+ u
Let x = Male, y = Female, z = Child. x+ C3 i: K( o4 E" V
6x + 3y + z/2 = 100 Formula 1
) F" S2 y/ b2 {; w- a; _4 Ux + y + z = 100 Formula 2( n) B# V+ T) T! I2 `
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
6 \' p& L2 @8 PSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
& B4 u8 d+ P# G" ? cTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇, J/ D3 a6 y- x' q+ y5 k+ i. j
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" @1 _( a- u9 k" t0 c3 L# k
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇8 N* @' t# n: i5 |8 B; [
Eventually, the answer is 20 female and 80 children and no male. |