That is a very simple mathematics question.
. ?% i; o' D5 c8 S/ e5.39.217.76Let x = Male, y = Female, z = Child公仔箱論壇/ l5 f+ y1 Y4 e# k! ^
6x + 3y + z/2 = 100 Formula 1
* @1 m2 z0 H9 Utvb now,tvbnow,bttvbx + y + z = 100 Formula 2
7 E5 {1 B# X H/ _; c: [2 QTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
) M- g* Q4 C; b) E! S. q1 c% USub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 45.39.217.76! K! v& L% V! B5 J" x7 J) h
Formula 4 can change into 11x + 5y = 100 Formula 50 X$ s- E' B# B' W, j: j6 H ]' q
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
`8 |1 F8 T& s$ P% W, a: jAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.76/ ^) U' r; u0 p# Q# @
Eventually, the answer is 20 female and 80 children and no male. |