That is a very simple mathematics question.
, _1 X; f. M+ D& \) l# _$ H* WLet x = Male, y = Female, z = Child
|* \# S, d2 r% {6x + 3y + z/2 = 100 Formula 1
' `4 s+ @; H$ L$ a0 o. r公仔箱論壇x + y + z = 100 Formula 2! C) _& C [" c
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
4 w' {- e* f( ]& B3 ptvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
- d- D; f G9 B9 q6 T& UFormula 4 can change into 11x + 5y = 100 Formula 5
1 s9 @6 ^7 t% t; B% L3 h! O9 [公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ d: i% a, h. y; y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
5 p' {' K- c- _% K" m& n5.39.217.76Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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