That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, F+ {3 H6 E9 b) F! `
Let x = Male, y = Female, z = Child g5 w. s: m; i1 f4 M) j
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb% @; D3 N) u2 g& i$ Y# \6 Z. `, l3 ]
x + y + z = 100 Formula 2
O; m0 H6 D0 ?0 v8 W" D5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇7 P# S1 `( `% @: L5 g
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
0 k% b2 R2 x4 p" v5 y8 }Formula 4 can change into 11x + 5y = 100 Formula 5
: d( G! W! H- v9 u {8 m% jIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.+ A6 s" p6 C; |3 Y8 h9 M5 y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.76: R8 `% u/ |- x0 U
Eventually, the answer is 20 female and 80 children and no male. |