That is a very simple mathematics question.
9 e7 |: H# w6 a( ~7 k5 w5 |$ RTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
0 w2 v+ S3 g* `. ?4 g. c! C5.39.217.766x + 3y + z/2 = 100 Formula 1
& I- u7 ]8 I$ P, Sx + y + z = 100 Formula 2
* ]1 S5 \+ s( K/ c; g5 iSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
. J. t7 C( s [1 F, Ztvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
1 p9 T3 R7 D. C- LTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, E* v) S5 e9 N1 L5 X6 a& E# B. N# z
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.tvb now,tvbnow,bttvb& a2 Y C+ R$ S
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
0 X* F8 Z# U' X( O7 ~TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |