That is a very simple mathematics question.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。( T6 L, Z+ F0 x- m1 Y$ P3 K
Let x = Male, y = Female, z = Child7 i) M! g! f2 S
6x + 3y + z/2 = 100 Formula 1- q6 T/ _ C* e3 ^# V
x + y + z = 100 Formula 2
7 G# S- {1 j' j3 X8 b5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
* z# O' E& u' O6 }, h1 t! R2 @Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
1 W/ t$ e+ c9 _3 _TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5: W( @ A9 g- \1 ?/ X
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.7 X0 Q% f' }1 y, n0 C0 q
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。7 Z% s& V! V/ }2 I$ ^9 D
Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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